Y=16x^2+480x

Solution for Y=16x^2+480x equation:

=16Y^2+480Y

We move all terms to the left:

-(16Y^2+480Y)=0

We get rid of parentheses

-16Y^2-480Y=0

a = -16; b = -480; c = 0;
Δ = b2-4ac
Δ = -4802-4·(-16)·0
Δ = 230400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{230400}=480$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-480)-480}{2*-16}=\frac{0}{-32}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-480)+480}{2*-16}=\frac{960}{-32}
=-30
$